Bus 173 Ajm

a) Construct cross tables from the smoothies data file – gender and level of health consciousness Health Consciousness| Male| Female| Subtotal|Very| 16| 13| 29|Moderately| 26| 29| 55|Slightly| 12| 8| 20|Not Very| 7| 2| 9|Subtotal| 61| 52| 113|

b) Desire for protein supplement level of health consciousness Health Consciousness| No| Yes| Subtotal|Very| 12| 17| 29|Moderately| 19| 36| 55|Slightly| 9| 11| 20|Not Very| 2| 7| 9|Subtotal| 42| 71| 113|

2.68a) Cross table of method of payment and day of purchase for Florin data file. Payment| M| T| W| Th| F| S| Tot|Am Ex| 7| 0| 3| 4| 3| 6| 23|MC| 1| 4| 4| 2| 4| 9| 16|Visa| 6| 6| 4| 5| 8| 10| 24|Cash| 3| 1| 0| 0| 3| 9| 16|Other| 2| 0| 4| 4| 7| 6| 23|Subtotal| 19| 11| 15| 15| 25| 40| 125|

b) Pie chart of rose color preference

3. 47 describe the charges for snappy lawn inc. for their lawn care services

3.49Cottona. Scatter plot

b. Ŷ=1506+.999 exportmarginal value= 0.99910.62Results for: BIGFISH.MTW

One-Sample T: Salmon Weight

Test of mu = 40 vs mu > 40

Variable N Mean StDev SE MeanSalmon Weigh 39 49.73 10.60 1.70

Variable 95.0% Lower Bound T PSalmon Weigh 46.86 5.73 0.000

at 5% level of significance we have strong enough evidence to reject the Ho that the true mean weight of salmon is no different than 40 in favourof Ha that the true mean weight is significantly greater than 40.

X crit = H0 + t crit (Sx) 40+ 1.686 (1.70) = 42.8662Population mean for β=.50power=.50: tcrit=0.0;42.8662+0.01.70 =42.8662 Population mean for β= .25 power=.75: tcrit=.681: 42.8662+ .6811.70 = 44.0239 Population mean for β= .10 power=.90: tcrit= 1.28: 42.8662+1.28(1.70) = 45.0422 Population mean for β= .05 (power=.95): tcrit=1.645: 42.8662+1.645(1.70) = 45.6627 or Beta=.50 .25 .10 & .05

1.0-0.9-.

0.8-0.7-0.6-0.5-0.4-0.3-0.2-0.1-

Power CURVEFor Beta=.50 .25 .10 & .05

1.0-0.9-0.8-0.7-0.6-0.5-0.4-0.3-0.2-0.1-0.0-40 42 43 44 45 46 POP Mean0.0-40 42 43 44 45 46 POP Mean

11.50

Results for: ANALYST PREDICTION.MTW

Test for Equal Variances

Level1 ANALYST ALevel2 ANALYST BConfLvl 95.0000

Bonferroni confidence intervals for standard deviations

Lower Sigma Upper N Factor Levels

2.81519 4.16314 7.69560 12 ANALYST A2.74153 4.05421 7.49424 12 ANALYST B

F-Test (normal distribution)

Test Statistic: 1.054P-Value : 0.931

Levene’s Test (any continuous distribution)

Test Statistic: 0.040P-Value : 0.843

There is insufficient evidence to suggest that the population varience differ between two forecasting analysis.

11.53.

Results for: CORN YIELD.MTW

Paired T-Test and CI: VARIETY A, VARIETY B

Paired T for VARIETY A – VARIETY B

N Mean StDev SE MeanVARIETY A 10 11.930 2.927 0.925VARIETY B 10 10.800 2.524 0.798Difference 10 1.130 1.612 0.510

90% CI for mean difference: (0.196, 2.064)T-Test of mean difference = 0 (vs not = 0): T-Value = 2.22 P-Value = 0.054

Reject Ho at the 10% but not the 5% level

11.55

Results for: OLE.MTW

Two-Sample T-Test and CI: Olesales, Carlsale

Two-sample T for Olesales vs Carlsale

N Mean StDev SE MeanOlesales 156 3791 5364 429Carlsale 156 2412 4249 340

Difference = mu Olesales – mu CarlsaleEstimate for difference: 137995% upper bound for difference: 2283T-Test of difference = 0 (vs <): T-Value = 2.52 P-Value = 0.994 DF = 294

Two-Sample T-Test and CI: Oleprice, Carlpric

Two-sample T for Oleprice vs Carlpric

N Mean StDev SE MeanOleprice 156 0.819 0.139 0.011Carlpric 156 0.819 0.120 0.0096

Difference = mu Oleprice – mu CarlpricEstimate for difference: -0.000795% CI for difference: (-0.0297, 0.0283)T-Test of difference = 0 (vs not =): T-Value = -0.05 P-Value = 0.962 DF = 303